REFLECTOR: Falling objects through the prop

[KeithHallsten]

Al,

When it comes to parachuting out of an elite-door Velocity, I would want to make sure I got a good push off of the door sill on the way out!  Also, since opening the door will likely start a roll, you wouldn't want to waste any time in making your departure.

Keith
 
  ----- Original Message ----- 
  From: Al Gietzen 
  To: 'Velocity Aircraft Owners and Builders list' 
  Sent: Thursday, March 10, 2005 9:02 PM
  Subject: RE: REFLECTOR: Re: Falling objects through the prop (Was NOSE WHEELGOTSIDEWAYS)


  Keith;



  Yes, I realized as I went back out to the shop that my "thinking-out-loud" analysis was all wrong; so I'm glad you followed up.  At first your 1.4 inches seemed too small, but the math is correct.  I think the fact that the object is initially at the speed of the plane makes a huge difference, and makes it likely a small metal object (small and dense) would clear the prop, probably by some margin. It only needs a ¼ of a second to make it.



  Some time ago I remember doing some back-of-the-napkin analysis with a couple of Long EZ drivers which concluded that a person could safely parachute out of an elite door Velocity, but it may have been a somewhat used cocktail napkin.



  Al



  Subject: REFLECTOR: Re: Falling objects through the prop (Was NOSE WHEEL GOTSIDEWAYS)



  Al,



  I follow you up through the point where you say the object will only fall 85 msec before the prop comes by.  However, as I recall the position formula is:

     X = X(init) + V(init)*T + 1/2 A*T*T.   If we use the initial elevation of the object as our datum, X(init) = 0, and if the initial downward velocity, V(init), is also zero.  If we further assume that the only acceleration acting on the object is gravity (32.2 ft/sec^2), then



    Distance Fallen = 1/2 * (32.2 ft/sec^2) * (0.085 sec) * (0.085 sec) = 0.117 ft  = 1.40 inch.



  So does your prop arc extend lower than 1.4 inches below the level of your nose gear door?  Sure!  



  However, we have neglected the fact that any object that falls off the plane is initially at the speed of the plane, not at rest, and it is slowed by air friction, so it is decelerating horizontally while is is accelerating vertically downward.  If we know the drag coefficient of the object that's falling, we could calculate that deceleration due to the relative wind, but that will be left as an exercise for the reader!  Suffice it to say that the object will actually fall significantly longer that 85 msec, and will therefore fall farther.  If the prop arc extends, say, 16 inches below the belly of the plane, we would need to have approximately 1.0 second of fall to clear the prop arc.  Is this likely?  Probably not.



  I think the conclusion is that anything that falls off the fuselage, even from the nose, is pretty likely to pass through the prop arc.



  Keith

        

    ----- Original Message ----- 

    From: Al Gietzen 

    To: 'Velocity Aircraft Owners and Builders list' 

    Sent: Thursday, March 10, 2005 8:08 AM

    Subject: RE: REFLECTOR: RE: NOSE WHEEL GOT SIDEWAYS



    Subject: REFLECTOR: RE: NOSE WHEEL GOT SIDEWAYS



    Tom



    You say believed you lost the "T" fitting in flight.  Did you check the Velocity high speed rotating strainer that's attached to the engine to see if it was detected, evidenced by leaving 'memory marks'?  Idle curiousity:  Can anything fall off the plane's fuselage without going through the prop at rotation speeds or above?



    Chuck



    Well, let's see; at 120 mph that's 176 ft/sec - so it takes about 85 msec to travel 15 ft.  If you drop something from the nose gear well, it will travel downward a max of about 30 - 35 in. before the prop goes by.  It might clear the prop.

    Just thinking out loud, check my math.

    Al


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