REFLECTOR:weak gas struts / beating a dead horse dept.
Chuck Jensen
reflector@tvbf.org
Fri, 2 Jan 2004 21:02:14 -0500
Well, "large or massive," as in a near perfect vacuum. In a triax
spectrometer (for neutron studies) a vacuum is developed in a relatively
small space by a several hp motor/pump run over 1-2 days period to get a
very-near perfect vacumm. And what did they use for a seal/lubricant on the
positive displacement pump...hydraulic fluid because even at near perfect
vacuum levels, it would not boil (or thus, form a bubble).
However, I stand corrected about Saddam being found in a spider hole. It
appears as though it was a s_ _ _t pit; a perfect fit.
Chuck Jensen
-----Original Message-----
From: reflector-admin@tvbf.org [mailto:reflector-admin@tvbf.org]On
Behalf Of Richard@Riley.net
Sent: Friday, January 02, 2004 5:26 PM
To: reflector@tvbf.org
Subject: RE: REFLECTOR:weak gas struts / beating a dead horse dept.
At 09:40 AM 1/2/04 -0500, you wrote:
>It is still correct that if you take a hydraulically locked system (no air,
>no water or gas contamination, no seal leakage), that the plunger will NOT
>move until you pull with a very large force; one great enough to vaporize
>the hydraulic fluid. Given that the vapor pressure of hydraulic fluid is
>very close to a perfect vacuum, it will take very large, even massive,
>mechanical force to form a bubble.
It all depends on your definition of "large, even massive."
Imagine a hydraulic cylinder floating in space, surrounded by vacuum. The
piston is fully retracted. Both ports are open, so there's nothing but
vacuum inside. You plug both ports, and pull on the shaft, what
happens? It pulls out with no resistance. The pressure comes from 2
places - atmospheric pressure on the shaft, and atmospheric pressure on the
fluid in the top half of the cyl.
If there's no vapor pressure to worry about - and I agree, with modern
hydraulic fluids, the pressure is so low we can ignore it - the force is
going to be 1 atmosphere (14.7lbs at sea level) times the area of the
piston. If you have a 2 inch ID cylinder, and a 1/2 inch shaft, and you're
at sea level, it will be 46.18 lbs (plus friction, but I'm ignoring
that.) At that point the fluid will cavitate, a void will form, and will
get bigger as the shaft is pulled out. A big force, but not that big,
especially if there's some leverage on the shaft.
Now, suppose instead of plugging the upper end of the cyl, we plug the
lower end? So as you try to pull the shaft out, you're trying to compress
the hydraulic fluid? Then, as you correctly point out, you're trying to do
the impossible, and the shaft won't move until you have enough force on it
for something to burst.
>I'm pretty sure this is all true, but then, I didn't think they'd find
>Saddam in a spider hole either.
To be totally accurate, they didn't. It was even better poetic
justice...http://www.sftt.org/cgi-bin/csNews/csNews.cgi?command=viewone&id=3
36&database=DefenseWatch%20Archive%2edb
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